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Share of each under muslim law for property inherited

(Querist) 04 September 2011 This query is : Resolved 
Dear Experts,
One of client is co owner of the property inherited from his father. they belong to muslim religion. his family i.e. client's father has left behind his wife, 2 Female children and 4 male children. I want to how much share each of these children will derive to the property.
prabhakar singh (Expert) 04 September 2011
Muslim succession is a bit complex hence you get it clarified the following::

1)They are shiya or sunni?
2)has the person died left also
a)father b)mother c) sister(s)
behind widow(s)4sons and 2daughters told by you already.??




Raj Kumar Makkad (Expert) 04 September 2011
It is necessary to clarify the legal questions related with the succession of muslim as raised by prabhakar singh first so that due reply may be given.
PrnBCRBant (Querist) 04 September 2011
Dear Experts,
1) Sunni
2) No father, mother or sister
R.Ramachandran (Expert) 04 September 2011
The complete legal heirs list is wanting from your post.
In any case, please find attached the inheritance table applicable to Sunni Muslims.
Still if you have doubts, you have to indicate the availability or not of the relationships mentioned in the first column of the table. Accordingly the shares will be worked out and indicated in respect of each of the heirs.

As can be seen from the table a daughter is a "Residuary" in the presence of a son.

If no other relations given in the table, other than the widow, are available, then the son and daughters being residuaries will inherit the property that is available after giving the share to their morhter.

Share of the daughter will be half of the share that a son gets.
R.Ramachandran (Expert) 04 September 2011
Omitted to attach the inheritance table. Now attached.
prabhakar singh (Expert) 04 September 2011
his wife (widow )will get 1/8

in 1-1/8=7/8 left as residuary which shall be divided in ratio of(son) 2:1(daughter).

hence sons2/3of 7/8=7/12
and daughters1/3of7/8=7/24

for 4sons 7/12/4 each son

for 2daughters7/24/2each daughter

so each son and daughter would get 7/48 and widow 6/48
[ w=6/48+(s1)7/48+(s2)7/48+(s3)7/48+(s4)7/48+(d1)7/48+(D2)7/48]=48/48=1
Raj Kumar Makkad (Expert) 05 September 2011
I do agree with prabhakar singh.


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